Reseni cviceni 3.1:
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1) Volame funkci newton_reseni s parametry
f = 'log(x)+(x-1)^3'
df = '1/x + 3*(x-1)^2'

2) Volame funkci newton_reseni s parametry
f = 'x + exp(-x^2) - 1'
df = '1 + exp(-x^2)*(-2*x)'


Reseni cviceni 3.2:
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1) nalezeni sqrt(2)
Volame funkci newton_reseni napriklad s parametry
f = 'x^2-2'
df = '2*x'
a vhodnou pocatecni aproximaci

2) nalezeni pi
Volame funkci newton_reseni napriklad s parametry
f = 'tan(x/4)-1/tan(x/4)'
df = '1/4*1/((cos(x/4))^2) + 1/4*1/((sin(x/4))^2)'
a vhodnou pocatecni aproximaci